Optimal. Leaf size=185 \[ -\frac {b \left (5 a^2+b^2\right ) \sin ^3(c+d x)}{3 d}+\frac {b \left (17 a^2+6 b^2\right ) \sin (c+d x)}{6 d}+\frac {a \left (5 a^2+18 b^2\right ) \sin (c+d x) \cos ^3(c+d x)}{24 d}+\frac {a \left (5 a^2+18 b^2\right ) \sin (c+d x) \cos (c+d x)}{16 d}+\frac {1}{16} a x \left (5 a^2+18 b^2\right )+\frac {13 a^2 b \sin ^5(c+d x)}{30 d}+\frac {a^2 \sin (c+d x) \cos ^5(c+d x) (a+b \sec (c+d x))}{6 d} \]
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Rubi [A] time = 0.23, antiderivative size = 185, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {3841, 4047, 2635, 8, 4044, 3013, 373} \[ -\frac {b \left (5 a^2+b^2\right ) \sin ^3(c+d x)}{3 d}+\frac {b \left (17 a^2+6 b^2\right ) \sin (c+d x)}{6 d}+\frac {a \left (5 a^2+18 b^2\right ) \sin (c+d x) \cos ^3(c+d x)}{24 d}+\frac {a \left (5 a^2+18 b^2\right ) \sin (c+d x) \cos (c+d x)}{16 d}+\frac {1}{16} a x \left (5 a^2+18 b^2\right )+\frac {13 a^2 b \sin ^5(c+d x)}{30 d}+\frac {a^2 \sin (c+d x) \cos ^5(c+d x) (a+b \sec (c+d x))}{6 d} \]
Antiderivative was successfully verified.
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Rule 8
Rule 373
Rule 2635
Rule 3013
Rule 3841
Rule 4044
Rule 4047
Rubi steps
\begin {align*} \int \cos ^6(c+d x) (a+b \sec (c+d x))^3 \, dx &=\frac {a^2 \cos ^5(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{6 d}+\frac {1}{6} \int \cos ^5(c+d x) \left (13 a^2 b+a \left (5 a^2+18 b^2\right ) \sec (c+d x)+2 b \left (2 a^2+3 b^2\right ) \sec ^2(c+d x)\right ) \, dx\\ &=\frac {a^2 \cos ^5(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{6 d}+\frac {1}{6} \int \cos ^5(c+d x) \left (13 a^2 b+2 b \left (2 a^2+3 b^2\right ) \sec ^2(c+d x)\right ) \, dx+\frac {1}{6} \left (a \left (5 a^2+18 b^2\right )\right ) \int \cos ^4(c+d x) \, dx\\ &=\frac {a \left (5 a^2+18 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{24 d}+\frac {a^2 \cos ^5(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{6 d}+\frac {1}{6} \int \cos ^3(c+d x) \left (2 b \left (2 a^2+3 b^2\right )+13 a^2 b \cos ^2(c+d x)\right ) \, dx+\frac {1}{8} \left (a \left (5 a^2+18 b^2\right )\right ) \int \cos ^2(c+d x) \, dx\\ &=\frac {a \left (5 a^2+18 b^2\right ) \cos (c+d x) \sin (c+d x)}{16 d}+\frac {a \left (5 a^2+18 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{24 d}+\frac {a^2 \cos ^5(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{6 d}+\frac {1}{16} \left (a \left (5 a^2+18 b^2\right )\right ) \int 1 \, dx-\frac {\operatorname {Subst}\left (\int \left (1-x^2\right ) \left (13 a^2 b+2 b \left (2 a^2+3 b^2\right )-13 a^2 b x^2\right ) \, dx,x,-\sin (c+d x)\right )}{6 d}\\ &=\frac {1}{16} a \left (5 a^2+18 b^2\right ) x+\frac {a \left (5 a^2+18 b^2\right ) \cos (c+d x) \sin (c+d x)}{16 d}+\frac {a \left (5 a^2+18 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{24 d}+\frac {a^2 \cos ^5(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{6 d}-\frac {\operatorname {Subst}\left (\int \left (17 a^2 b \left (1+\frac {6 b^2}{17 a^2}\right )-6 b \left (5 a^2+b^2\right ) x^2+13 a^2 b x^4\right ) \, dx,x,-\sin (c+d x)\right )}{6 d}\\ &=\frac {1}{16} a \left (5 a^2+18 b^2\right ) x+\frac {b \left (17 a^2+6 b^2\right ) \sin (c+d x)}{6 d}+\frac {a \left (5 a^2+18 b^2\right ) \cos (c+d x) \sin (c+d x)}{16 d}+\frac {a \left (5 a^2+18 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{24 d}+\frac {a^2 \cos ^5(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{6 d}-\frac {b \left (5 a^2+b^2\right ) \sin ^3(c+d x)}{3 d}+\frac {13 a^2 b \sin ^5(c+d x)}{30 d}\\ \end {align*}
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Mathematica [A] time = 0.34, size = 159, normalized size = 0.86 \[ \frac {45 \left (5 a^3+16 a b^2\right ) \sin (2 (c+d x))+45 a^3 \sin (4 (c+d x))+5 a^3 \sin (6 (c+d x))+300 a^3 c+300 a^3 d x+360 b \left (5 a^2+2 b^2\right ) \sin (c+d x)+300 a^2 b \sin (3 (c+d x))+36 a^2 b \sin (5 (c+d x))+90 a b^2 \sin (4 (c+d x))+1080 a b^2 c+1080 a b^2 d x+80 b^3 \sin (3 (c+d x))}{960 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.49, size = 132, normalized size = 0.71 \[ \frac {15 \, {\left (5 \, a^{3} + 18 \, a b^{2}\right )} d x + {\left (40 \, a^{3} \cos \left (d x + c\right )^{5} + 144 \, a^{2} b \cos \left (d x + c\right )^{4} + 10 \, {\left (5 \, a^{3} + 18 \, a b^{2}\right )} \cos \left (d x + c\right )^{3} + 384 \, a^{2} b + 160 \, b^{3} + 16 \, {\left (12 \, a^{2} b + 5 \, b^{3}\right )} \cos \left (d x + c\right )^{2} + 15 \, {\left (5 \, a^{3} + 18 \, a b^{2}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{240 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.27, size = 431, normalized size = 2.33 \[ \frac {15 \, {\left (5 \, a^{3} + 18 \, a b^{2}\right )} {\left (d x + c\right )} - \frac {2 \, {\left (165 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} - 720 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} + 450 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} - 240 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} - 25 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 1680 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 630 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 880 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 450 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 3744 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 180 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 1440 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 450 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 3744 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 180 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 1440 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 25 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 1680 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 630 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 880 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 165 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 720 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 450 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 240 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{6}}}{240 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 1.49, size = 145, normalized size = 0.78 \[ \frac {a^{3} \left (\frac {\left (\cos ^{5}\left (d x +c \right )+\frac {5 \left (\cos ^{3}\left (d x +c \right )\right )}{4}+\frac {15 \cos \left (d x +c \right )}{8}\right ) \sin \left (d x +c \right )}{6}+\frac {5 d x}{16}+\frac {5 c}{16}\right )+\frac {3 a^{2} b \left (\frac {8}{3}+\cos ^{4}\left (d x +c \right )+\frac {4 \left (\cos ^{2}\left (d x +c \right )\right )}{3}\right ) \sin \left (d x +c \right )}{5}+3 b^{2} a \left (\frac {\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )+\frac {b^{3} \left (2+\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{3}}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.38, size = 145, normalized size = 0.78 \[ -\frac {5 \, {\left (4 \, \sin \left (2 \, d x + 2 \, c\right )^{3} - 60 \, d x - 60 \, c - 9 \, \sin \left (4 \, d x + 4 \, c\right ) - 48 \, \sin \left (2 \, d x + 2 \, c\right )\right )} a^{3} - 192 \, {\left (3 \, \sin \left (d x + c\right )^{5} - 10 \, \sin \left (d x + c\right )^{3} + 15 \, \sin \left (d x + c\right )\right )} a^{2} b - 90 \, {\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} a b^{2} + 320 \, {\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} b^{3}}{960 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 3.30, size = 350, normalized size = 1.89 \[ \frac {\left (-\frac {11\,a^3}{8}+6\,a^2\,b-\frac {15\,a\,b^2}{4}+2\,b^3\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}+\left (\frac {5\,a^3}{24}+14\,a^2\,b-\frac {21\,a\,b^2}{4}+\frac {22\,b^3}{3}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9+\left (-\frac {15\,a^3}{4}+\frac {156\,a^2\,b}{5}-\frac {3\,a\,b^2}{2}+12\,b^3\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+\left (\frac {15\,a^3}{4}+\frac {156\,a^2\,b}{5}+\frac {3\,a\,b^2}{2}+12\,b^3\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+\left (-\frac {5\,a^3}{24}+14\,a^2\,b+\frac {21\,a\,b^2}{4}+\frac {22\,b^3}{3}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+\left (\frac {11\,a^3}{8}+6\,a^2\,b+\frac {15\,a\,b^2}{4}+2\,b^3\right )\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}+6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+15\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+20\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+15\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}+\frac {a\,\mathrm {atan}\left (\frac {a\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (5\,a^2+18\,b^2\right )}{8\,\left (\frac {5\,a^3}{8}+\frac {9\,a\,b^2}{4}\right )}\right )\,\left (5\,a^2+18\,b^2\right )}{8\,d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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